Base | Representation |
---|---|
bin | 11101100100001100110101… |
… | …100010001010000111110011 |
3 | 122001101211211021010201021221 |
4 | 131210030311202022013303 |
5 | 114020412023424030303 |
6 | 1140315233143325511 |
7 | 36250301134142101 |
oct | 3544146542120763 |
9 | 561354737121257 |
10 | 130031033033203 |
11 | 38482940277405 |
12 | 12700a75a50897 |
13 | 5772b48981c23 |
14 | 241776d8b2c71 |
15 | 1007613c2b4bd |
hex | 76433588a1f3 |
130031033033203 has 2 divisors, whose sum is σ = 130031033033204. Its totient is φ = 130031033033202.
The previous prime is 130031033033191. The next prime is 130031033033233. The reversal of 130031033033203 is 302330330130031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130031033033203 - 213 = 130031033025011 is a prime.
It is not a weakly prime, because it can be changed into another prime (130031033033233) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65015516516601 + 65015516516602.
It is an arithmetic number, because the mean of its divisors is an integer number (65015516516602).
Almost surely, 2130031033033203 is an apocalyptic number.
130031033033203 is a deficient number, since it is larger than the sum of its proper divisors (1).
130031033033203 is an equidigital number, since it uses as much as digits as its factorization.
130031033033203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4374, while the sum is 25.
Adding to 130031033033203 its reverse (302330330130031), we get a palindrome (432361363163234).
The spelling of 130031033033203 in words is "one hundred thirty trillion, thirty-one billion, thirty-three million, thirty-three thousand, two hundred three".
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