130031119957 has 2 divisors, whose sum is σ = 130031119958. Its totient is φ = 130031119956.

The previous prime is 130031119951. The next prime is 130031119961. The reversal of 130031119957 is 759911130031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 84280476721 + 45750643236 = 290311^2 + 213894^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130031119957 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130031119951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65015559978 + 65015559979.

It is an arithmetic number, because the mean of its divisors is an integer number (65015559979).

Almost surely, 2^130031119957 is an apocalyptic number.

It is an amenable number.

130031119957 is a deficient number, since it is larger than the sum of its proper divisors (1).

130031119957 is an equidigital number, since it uses as much as digits as its factorization.

130031119957 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25515, while the sum is 40.

Adding to 130031119957 its reverse (759911130031), we get a palindrome (889942249988).

The spelling of 130031119957 in words is "one hundred thirty billion, thirty-one million, one hundred nineteen thousand, nine hundred fifty-seven".