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130033112137 is a prime number
BaseRepresentation
bin111100100011010010…
…0111101010001001001
3110102122020020111221021
41321012210331101021
54112301434042022
6135423020512441
712252225134125
oct1710644752111
9412566214837
10130033112137
1150168335835
122124b9ab721
13c3539c9206
146417a48585
1535b0c047c7
hex1e4693d449

130033112137 has 2 divisors, whose sum is σ = 130033112138. Its totient is φ = 130033112136.

The previous prime is 130033112117. The next prime is 130033112141. The reversal of 130033112137 is 731211330031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97382067721 + 32651044416 = 312061^2 + 180696^2 .

It is a cyclic number.

It is not a de Polignac number, because 130033112137 - 215 = 130033079369 is a prime.

It is a super-2 number, since 2×1300331121372 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130033112117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65016556068 + 65016556069.

It is an arithmetic number, because the mean of its divisors is an integer number (65016556069).

Almost surely, 2130033112137 is an apocalyptic number.

It is an amenable number.

130033112137 is a deficient number, since it is larger than the sum of its proper divisors (1).

130033112137 is an equidigital number, since it uses as much as digits as its factorization.

130033112137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1134, while the sum is 25.

Adding to 130033112137 its reverse (731211330031), we get a palindrome (861244442168).

The spelling of 130033112137 in words is "one hundred thirty billion, thirty-three million, one hundred twelve thousand, one hundred thirty-seven".