Base | Representation |
---|---|
bin | 111100100011010010… |
… | …0111110100100111011 |
3 | 110102122020020210021212 |
4 | 1321012210332210323 |
5 | 4112301434224444 |
6 | 135423020553335 |
7 | 12252225155555 |
oct | 1710644764473 |
9 | 412566223255 |
10 | 130033117499 |
11 | 5016833986a |
12 | 2124b9b284b |
13 | c3539cb79c |
14 | 6417a4a4d5 |
15 | 35b0c0619e |
hex | 1e4693e93b |
130033117499 has 2 divisors, whose sum is σ = 130033117500. Its totient is φ = 130033117498.
The previous prime is 130033117493. The next prime is 130033117507. The reversal of 130033117499 is 994711330031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130033117499 - 212 = 130033113403 is a prime.
It is a super-2 number, since 2×1300331174992 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130033117493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65016558749 + 65016558750.
It is an arithmetic number, because the mean of its divisors is an integer number (65016558750).
Almost surely, 2130033117499 is an apocalyptic number.
130033117499 is a deficient number, since it is larger than the sum of its proper divisors (1).
130033117499 is an equidigital number, since it uses as much as digits as its factorization.
130033117499 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 61236, while the sum is 41.
The spelling of 130033117499 in words is "one hundred thirty billion, thirty-three million, one hundred seventeen thousand, four hundred ninety-nine".
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