130033117500 has 480 divisors, whose sum is σ = 448088965632. Its totient is φ = 28924800000.

The previous prime is 130033117499. The next prime is 130033117507. The reversal of 130033117500 is 5711330031.

It is a super-2 number, since 2×130033117500² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130033117507) by changing a digit.

It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 282067270 + ... + 282067730.

Almost surely, 2^130033117500 is an apocalyptic number.

130033117500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130033117500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (224044482816).

130033117500 is an abundant number, since it is smaller than the sum of its proper divisors (318055848132).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130033117500 is a wasteful number, since it uses less digits than its factorization.

130033117500 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 775 (or 758 counting only the distinct ones).

The product of its (nonzero) digits is 945, while the sum is 24.

Adding to 130033117500 its reverse (5711330031), we get a palindrome (135744447531).

The spelling of 130033117500 in words is "one hundred thirty billion, thirty-three million, one hundred seventeen thousand, five hundred".