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13003312203000 = 2332537206401781
BaseRepresentation
bin1011110100111001000111…
…0011100000010011111000
31201001002211011222212121200
42331032101303200103320
53201021240410444000
643353350020334200
72511313125020040
oct275162163402370
951032734885550
1013003312203000
114163745819949
121560166b44360
1373428cc50c52
1432d513c9a720
151783a534a500
hexbd391ce04f8

13003312203000 has 192 divisors, whose sum is σ = 50229937667520. Its totient is φ = 2972185632000.

The previous prime is 13003312202917. The next prime is 13003312203031. The reversal of 13003312203000 is 30221330031.

13003312203000 is a `hidden beast` number, since 1 + 30 + 0 + 3 + 312 + 20 + 300 + 0 = 666.

13003312203000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×130033122030002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 103137891 + ... + 103263890.

It is an arithmetic number, because the mean of its divisors is an integer number (261614258685).

Almost surely, 213003312203000 is an apocalyptic number.

13003312203000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13003312203000 is an abundant number, since it is smaller than the sum of its proper divisors (37226625464520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13003312203000 is a wasteful number, since it uses less digits than its factorization.

13003312203000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 206401815 (or 206401798 counting only the distinct ones).

The product of its (nonzero) digits is 324, while the sum is 18.

Adding to 13003312203000 its reverse (30221330031), we get a palindrome (13033533533031).

The spelling of 13003312203000 in words is "thirteen trillion, three billion, three hundred twelve million, two hundred three thousand".