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13003312310000 = 24547935394651
BaseRepresentation
bin1011110100111001000111…
…0011111010011011110000
31201001002211012012022101122
42331032101303322123300
53201021240422410000
643353350022521412
72511313125644015
oct275162163723360
951032735168348
1013003312310000
114163745892281
121560166b96268
1373428cc8a86c
1432d513cc770c
151783a536c085
hexbd391cfa6f0

13003312310000 has 200 divisors, whose sum is σ = 31896694790400. Its totient is φ = 5132930400000.

The previous prime is 13003312309979. The next prime is 13003312310069. The reversal of 13003312310000 is 1321330031.

It is a tau number, because it is divible by the number of its divisors (200).

It is a super-2 number, since 2×130033123100002 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 2795807675 + ... + 2795812325.

It is an arithmetic number, because the mean of its divisors is an integer number (159483473952).

Almost surely, 213003312310000 is an apocalyptic number.

13003312310000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13003312310000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15948347395200).

13003312310000 is an abundant number, since it is smaller than the sum of its proper divisors (18893382480400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13003312310000 is an equidigital number, since it uses as much as digits as its factorization.

13003312310000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8297 (or 8276 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 13003312310000 its reverse (1321330031), we get a palindrome (13004633640031).

The spelling of 13003312310000 in words is "thirteen trillion, three billion, three hundred twelve million, three hundred ten thousand".