13003313120130 has 16 divisors (see below), whose sum is σ = 31207951488384. Its totient is φ = 3467550165360.

The previous prime is 13003313120011. The next prime is 13003313120137. The reversal of 13003313120130 is 3102131330031.

It is a super-2 number, since 2×13003313120130² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13003313120097 and 13003313120106.

It is not an unprimeable number, because it can be changed into a prime (13003313120137) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 216721885306 + ... + 216721885365.

It is an arithmetic number, because the mean of its divisors is an integer number (1950496968024).

Almost surely, 2^{13003313120130} is an apocalyptic number.

13003313120130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13003313120130 is an abundant number, since it is smaller than the sum of its proper divisors (18204638368254).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13003313120130 is a wasteful number, since it uses less digits than its factorization.

13003313120130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 433443770681.

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 13003313120130 its reverse (3102131330031), we get a palindrome (16105444450161).

The spelling of 13003313120130 in words is "thirteen trillion, three billion, three hundred thirteen million, one hundred twenty thousand, one hundred thirty".