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130033140050000 = 245511243574933
BaseRepresentation
bin11101100100001110110011…
…000111110010100001010000
3122001102001021002212020222002
4131210032303013302201100
5114020430332323100000
61140320222212133132
736250404300402155
oct3544166307624120
9561361232766862
10130033140050000
1138483821668300
12127013636071a8
1357730c3358825
1424178cd66822c
1510076d8bcc8d5
hex7643b31f2850

130033140050000 has 360 divisors, whose sum is σ = 346283616726936. Its totient is φ = 47264342400000.

The previous prime is 130033140049991. The next prime is 130033140050059. The reversal of 130033140050000 is 50041330031.

It is a happy number.

It can be written as a sum of positive squares in 12 ways, for example, as 117237095001664 + 12796045048336 = 10827608^2 + 3577156^2 .

It is a super-2 number, since 2×1300331400500002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 26359847534 + ... + 26359852466.

Almost surely, 2130033140050000 is an apocalyptic number.

130033140050000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130033140050000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (173141808363468).

130033140050000 is an abundant number, since it is smaller than the sum of its proper divisors (216250476676936).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130033140050000 is an equidigital number, since it uses as much as digits as its factorization.

130033140050000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9345 (or 9308 counting only the distinct ones).

The product of its (nonzero) digits is 540, while the sum is 20.

Adding to 130033140050000 its reverse (50041330031), we get a palindrome (130083181380031).

The spelling of 130033140050000 in words is "one hundred thirty trillion, thirty-three billion, one hundred forty million, fifty thousand".