Base | Representation |
---|---|
bin | 1011110100111001001011… |
… | …1100010111011110000110 |
3 | 1201001002212111221021022021 |
4 | 2331032102330113132012 |
5 | 3201021310303201202 |
6 | 43353351541553354 |
7 | 2511313446251044 |
oct | 275162274273606 |
9 | 51032774837267 |
10 | 13003331303302 |
11 | 416375558521a |
12 | 156017141585a |
13 | 734293baa9c2 |
14 | 32d51662d394 |
15 | 1783a6d6ea37 |
hex | bd392f17786 |
13003331303302 has 4 divisors (see below), whose sum is σ = 19504996954956. Its totient is φ = 6501665651650.
The previous prime is 13003331303279. The next prime is 13003331303537. The reversal of 13003331303302 is 20330313330031.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×130033313033022 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3250832825824 + ... + 3250832825827.
It is an arithmetic number, because the mean of its divisors is an integer number (4876249238739).
Almost surely, 213003331303302 is an apocalyptic number.
13003331303302 is a deficient number, since it is larger than the sum of its proper divisors (6501665651654).
13003331303302 is an equidigital number, since it uses as much as digits as its factorization.
13003331303302 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6501665651653.
The product of its (nonzero) digits is 4374, while the sum is 25.
Adding to 13003331303302 its reverse (20330313330031), we get a palindrome (33333644633333).
The spelling of 13003331303302 in words is "thirteen trillion, three billion, three hundred thirty-one million, three hundred three thousand, three hundred two".
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