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130033405052497 is a prime number
BaseRepresentation
bin11101100100001111000010…
…111010101100011001010001
3122001102001221120111210001101
4131210033002322230121101
5114020431403143134442
61140320304400104401
736250413666030202
oct3544170272543121
9561361846453041
10130033405052497
1138483948208631
1212701418305101
135773136221a3b
14241791692b5a9
1510077020c6cb7
hex7643c2eac651

130033405052497 has 2 divisors, whose sum is σ = 130033405052498. Its totient is φ = 130033405052496.

The previous prime is 130033405052483. The next prime is 130033405052519. The reversal of 130033405052497 is 794250504330031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 84980299762576 + 45053105289921 = 9218476^2 + 6712161^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130033405052497 is a prime.

It is not a weakly prime, because it can be changed into another prime (130033405022497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65016702526248 + 65016702526249.

It is an arithmetic number, because the mean of its divisors is an integer number (65016702526249).

Almost surely, 2130033405052497 is an apocalyptic number.

It is an amenable number.

130033405052497 is a deficient number, since it is larger than the sum of its proper divisors (1).

130033405052497 is an equidigital number, since it uses as much as digits as its factorization.

130033405052497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1360800, while the sum is 46.

The spelling of 130033405052497 in words is "one hundred thirty trillion, thirty-three billion, four hundred five million, fifty-two thousand, four hundred ninety-seven".