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130033405052519 is a prime number
BaseRepresentation
bin11101100100001111000010…
…111010101100011001100111
3122001102001221120111210002012
4131210033002322230121213
5114020431403143140034
61140320304400104435
736250413666030233
oct3544170272543147
9561361846453065
10130033405052519
1138483948208651
121270141830511b
135773136221a57
14241791692b5c3
1510077020c6cce
hex7643c2eac667

130033405052519 has 2 divisors, whose sum is σ = 130033405052520. Its totient is φ = 130033405052518.

The previous prime is 130033405052497. The next prime is 130033405052533. The reversal of 130033405052519 is 915250504330031.

It is a strong prime.

It is an emirp because it is prime and its reverse (915250504330031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130033405052519 - 212 = 130033405048423 is a prime.

It is a super-2 number, since 2×1300334050525192 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130033405052549) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65016702526259 + 65016702526260.

It is an arithmetic number, because the mean of its divisors is an integer number (65016702526260).

Almost surely, 2130033405052519 is an apocalyptic number.

130033405052519 is a deficient number, since it is larger than the sum of its proper divisors (1).

130033405052519 is an equidigital number, since it uses as much as digits as its factorization.

130033405052519 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243000, while the sum is 41.

The spelling of 130033405052519 in words is "one hundred thirty trillion, thirty-three billion, four hundred five million, fifty-two thousand, five hundred nineteen".