Base | Representation |
---|---|
bin | 1011110100111001100110… |
… | …0111011011100000011011 |
3 | 1201001010011022121000121102 |
4 | 2331032121213123200123 |
5 | 3201022022433132243 |
6 | 43353411021302015 |
7 | 2511316305652553 |
oct | 275163147334033 |
9 | 51033138530542 |
10 | 13003443255323 |
11 | 416380279a454 |
12 | 15601a2a0490b |
13 | 7342b11476c1 |
14 | 32d527452163 |
15 | 1783b1ad59b8 |
hex | bd3999db81b |
13003443255323 has 2 divisors, whose sum is σ = 13003443255324. Its totient is φ = 13003443255322.
The previous prime is 13003443255287. The next prime is 13003443255347. The reversal of 13003443255323 is 32355234430031.
It is a strong prime.
It is an emirp because it is prime and its reverse (32355234430031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13003443255323 - 218 = 13003442993179 is a prime.
It is not a weakly prime, because it can be changed into another prime (13003443255823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501721627661 + 6501721627662.
It is an arithmetic number, because the mean of its divisors is an integer number (6501721627662).
Almost surely, 213003443255323 is an apocalyptic number.
13003443255323 is a deficient number, since it is larger than the sum of its proper divisors (1).
13003443255323 is an equidigital number, since it uses as much as digits as its factorization.
13003443255323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 388800, while the sum is 38.
Adding to 13003443255323 its reverse (32355234430031), we get a palindrome (45358677685354).
The spelling of 13003443255323 in words is "thirteen trillion, three billion, four hundred forty-three million, two hundred fifty-five thousand, three hundred twenty-three".
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