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130035343300 = 22521300353433
BaseRepresentation
bin111100100011010110…
…1011101111111000100
3110102122101102212111221
41321012231131333010
54112303021441200
6135423140410124
712252253116022
oct1710655357704
9412571385457
10130035343300
115016961a075
12212506a6944
13c3542ca925
146418069712
1535b0ee591a
hex1e46b5dfc4

130035343300 has 18 divisors (see below), whose sum is σ = 282176695178. Its totient is φ = 52014137280.

The previous prime is 130035343267. The next prime is 130035343337. The reversal of 130035343300 is 3343530031.

It can be written as a sum of positive squares in 3 ways, for example, as 41512432516 + 88522910784 = 203746^2 + 297528^2 .

It is a Harshad number since it is a multiple of its sum of digits (25).

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 650176617 + ... + 650176816.

Almost surely, 2130035343300 is an apocalyptic number.

130035343300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

130035343300 is an abundant number, since it is smaller than the sum of its proper divisors (152141351878).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130035343300 is a wasteful number, since it uses less digits than its factorization.

130035343300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1300353447 (or 1300353440 counting only the distinct ones).

The product of its (nonzero) digits is 4860, while the sum is 25.

Adding to 130035343300 its reverse (3343530031), we get a palindrome (133378873331).

The spelling of 130035343300 in words is "one hundred thirty billion, thirty-five million, three hundred forty-three thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 1300353433 2600706866 5201413732 6501767165 13003534330 26007068660 32508835825 65017671650 130035343300