1300376125440 has 816 divisors, whose sum is σ = 5345029243008. Its totient is φ = 297101426688.

The previous prime is 1300376125397. The next prime is 1300376125469. The reversal of 1300376125440 is 445216730031.

1300376125440 is a `hidden beast` number, since 1 + 3 + 0 + 0 + 37 + 612 + 5 + 4 + 4 + 0 = 666.

It is a super-2 number, since 2×1300376125440² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a junction number, because it is equal to n+sod(n) for n = 1300376125395 and 1300376125404.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 557382514 + ... + 557384846.

Almost surely, 2^{1300376125440} is an apocalyptic number.

1300376125440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1300376125440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2672514621504).

1300376125440 is an abundant number, since it is smaller than the sum of its proper divisors (4044653117568).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300376125440 is an frugal number, since it uses more digits than its factorization.

1300376125440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2392 (or 2350 counting only the distinct ones).

The product of its (nonzero) digits is 60480, while the sum is 36.

The spelling of 1300376125440 in words is "one trillion, three hundred billion, three hundred seventy-six million, one hundred twenty-five thousand, four hundred forty".