1300401103 has 2 divisors, whose sum is σ = 1300401104. Its totient is φ = 1300401102.

The previous prime is 1300401083. The next prime is 1300401107. The reversal of 1300401103 is 3011040031.

It is a strong prime.

It is an emirp because it is prime and its reverse (3011040031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1300401103 - 2¹³ = 1300392911 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300401107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650200551 + 650200552.

It is an arithmetic number, because the mean of its divisors is an integer number (650200552).

Almost surely, 2^1300401103 is an apocalyptic number.

1300401103 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300401103 is an equidigital number, since it uses as much as digits as its factorization.

1300401103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 1300401103 is about 36061.0746234773. The cubic root of 1300401103 is about 1091.5051179188.

Adding to 1300401103 its reverse (3011040031), we get a palindrome (4311441134).

The spelling of 1300401103 in words is "one billion, three hundred million, four hundred one thousand, one hundred three".