1300402103 has 32 divisors (see below), whose sum is σ = 1756554240. Its totient is φ = 935232480.

The previous prime is 1300402099. The next prime is 1300402141. The reversal of 1300402103 is 3012040031.

It is not a de Polignac number, because 1300402103 - 2² = 1300402099 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300401103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 165326 + ... + 173012.

It is an arithmetic number, because the mean of its divisors is an integer number (54892320).

Almost surely, 2^1300402103 is an apocalyptic number.

1300402103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1300402103 is a deficient number, since it is larger than the sum of its proper divisors (456152137).

1300402103 is an equidigital number, since it uses as much as digits as its factorization.

1300402103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7744 (or 7718 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 14.

The square root of 1300402103 is about 36061.0884888407. The cubic root of 1300402103 is about 1091.5053977055.

Adding to 1300402103 its reverse (3012040031), we get a palindrome (4312442134).

The spelling of 1300402103 in words is "one billion, three hundred million, four hundred two thousand, one hundred three".