Base | Representation |
---|---|
bin | 1011110100111011110000… |
… | …0111100110001111011000 |
3 | 1201001011122122211001101112 |
4 | 2331032330013212033120 |
5 | 3201024214130110430 |
6 | 43353544300235452 |
7 | 2511336535115144 |
oct | 275167407461730 |
9 | 51034578731345 |
10 | 13004022113240 |
11 | 4163a7a517a24 |
12 | 156032483bb88 |
13 | 734374050092 |
14 | 32d580294224 |
15 | 1783e7829195 |
hex | bd3bc1e63d8 |
13004022113240 has 128 divisors (see below), whose sum is σ = 29633541275520. Its totient is φ = 5135535820800.
The previous prime is 13004022113231. The next prime is 13004022113311. The reversal of 13004022113240 is 4231122040031.
It is a super-2 number, since 2×130040221132402 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 910574900 + ... + 910589180.
It is an arithmetic number, because the mean of its divisors is an integer number (231512041215).
Almost surely, 213004022113240 is an apocalyptic number.
13004022113240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13004022113240 is an abundant number, since it is smaller than the sum of its proper divisors (16629519162280).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13004022113240 is a wasteful number, since it uses less digits than its factorization.
13004022113240 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15373 (or 15369 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 13004022113240 its reverse (4231122040031), we get a palindrome (17235144153271).
The spelling of 13004022113240 in words is "thirteen trillion, four billion, twenty-two million, one hundred thirteen thousand, two hundred forty".
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