13004051130 has 48 divisors (see below), whose sum is σ = 38640610944. Its totient is φ = 2972354400.

The previous prime is 13004051129. The next prime is 13004051131. The reversal of 13004051130 is 3115040031.

13004051130 is a `hidden beast` number, since 130 + 0 + 405 + 1 + 130 = 666.

It is an interprime number because it is at equal distance from previous prime (13004051129) and next prime (13004051131).

It is a super-3 number, since 3×13004051130³ (a number of 31 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (13004051131) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 10320046 + ... + 10321305.

It is an arithmetic number, because the mean of its divisors is an integer number (805012728).

Almost surely, 2^13004051130 is an apocalyptic number.

13004051130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13004051130 is an abundant number, since it is smaller than the sum of its proper divisors (25636559814).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13004051130 is a wasteful number, since it uses less digits than its factorization.

13004051130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20641371 (or 20641368 counting only the distinct ones).

The product of its (nonzero) digits is 180, while the sum is 18.

Adding to 13004051130 its reverse (3115040031), we get a palindrome (16119091161).

The spelling of 13004051130 in words is "thirteen billion, four million, fifty-one thousand, one hundred thirty".