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1300410132 = 223715481073
BaseRepresentation
bin100110110000010…
…1010111100010100
310100121221200100020
41031200222330110
510130401111012
6333012145140
744140206120
oct11540527424
93317850306
101300410132
1160805841a
123036081b0
1317954c868
14c49ca580
1579271a8c
hex4d82af14

1300410132 has 24 divisors (see below), whose sum is σ = 3467760576. Its totient is φ = 371545728.

The previous prime is 1300410077. The next prime is 1300410143. The reversal of 1300410132 is 2310140031.

It is a super-2 number, since 2×13004101322 = 3382133022816514848, which contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7740453 + ... + 7740620.

It is an arithmetic number, because the mean of its divisors is an integer number (144490024).

Almost surely, 21300410132 is an apocalyptic number.

1300410132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1300410132 is an abundant number, since it is smaller than the sum of its proper divisors (2167350444).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300410132 is a wasteful number, since it uses less digits than its factorization.

1300410132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15481087 (or 15481085 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 1300410132 is about 36061.1998136501. The cubic root of 1300410132 is about 1091.5076441078.

Adding to 1300410132 its reverse (2310140031), we get a palindrome (3610550163).

The spelling of 1300410132 in words is "one billion, three hundred million, four hundred ten thousand, one hundred thirty-two".

Divisors: 1 2 3 4 6 7 12 14 21 28 42 84 15481073 30962146 46443219 61924292 92886438 108367511 185772876 216735022 325102533 433470044 650205066 1300410132