Base | Representation |
---|---|
bin | 11000001110001101… |
… | …10000110001101111 |
3 | 1020120021112111020221 |
4 | 30013012300301233 |
5 | 203113023140210 |
6 | 5550215152211 |
7 | 640153103611 |
oct | 140706606157 |
9 | 36507474227 |
10 | 13004115055 |
11 | 5573536128 |
12 | 262b075667 |
13 | 12c31b2a49 |
14 | 8b511adb1 |
15 | 5119b61da |
hex | 3071b0c6f |
13004115055 has 16 divisors (see below), whose sum is σ = 15807949920. Its totient is φ = 10268189568.
The previous prime is 13004115037. The next prime is 13004115161. The reversal of 13004115055 is 55051140031.
It is a happy number.
13004115055 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13004115055 - 211 = 13004113007 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 439261 + ... + 467929.
It is an arithmetic number, because the mean of its divisors is an integer number (987996870).
Almost surely, 213004115055 is an apocalyptic number.
13004115055 is a deficient number, since it is larger than the sum of its proper divisors (2803834865).
13004115055 is a wasteful number, since it uses less digits than its factorization.
13004115055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29850.
The product of its (nonzero) digits is 1500, while the sum is 25.
Adding to 13004115055 its reverse (55051140031), we get a palindrome (68055255086).
The spelling of 13004115055 in words is "thirteen billion, four million, one hundred fifteen thousand, fifty-five".
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