1300412112 has 40 divisors (see below), whose sum is σ = 3409546656. Its totient is φ = 426999936.

The previous prime is 1300412107. The next prime is 1300412131. The reversal of 1300412112 is 2112140031.

It is a super-2 number, since 2×1300412112² = 3382143322072601088, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1300412091 and 1300412100.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 198963 + ... + 205394.

Almost surely, 2^1300412112 is an apocalyptic number.

1300412112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1300412112 is an abundant number, since it is smaller than the sum of its proper divisors (2109134544).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300412112 is a wasteful number, since it uses less digits than its factorization.

1300412112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 404435 (or 404429 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 1300412112 is about 36061.2272669692. The cubic root of 1300412112 is about 1091.5081980828.

Adding to 1300412112 its reverse (2112140031), we get a palindrome (3412552143).

The spelling of 1300412112 in words is "one billion, three hundred million, four hundred twelve thousand, one hundred twelve".