130041412414142 has 8 divisors (see below), whose sum is σ = 195072980199600. Its totient is φ = 65017085680944.

The previous prime is 130041412414061. The next prime is 130041412414163. The reversal of 130041412414142 is 241414214140031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×130041412414142³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130041412414099 and 130041412414108.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1810218167 + ... + 1810290002.

It is an arithmetic number, because the mean of its divisors is an integer number (24384122524950).

Almost surely, 2^{130041412414142} is an apocalyptic number.

130041412414142 is a deficient number, since it is larger than the sum of its proper divisors (65031567785458).

130041412414142 is a wasteful number, since it uses less digits than its factorization.

130041412414142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3620526130.

The product of its (nonzero) digits is 12288, while the sum is 32.

Adding to 130041412414142 its reverse (241414214140031), we get a palindrome (371455626554173).

The spelling of 130041412414142 in words is "one hundred thirty trillion, forty-one billion, four hundred twelve million, four hundred fourteen thousand, one hundred forty-two".