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13004213333 is a prime number
BaseRepresentation
bin11000001110001110…
…01000110001010101
31020120021201111001212
430013013020301111
5203113034311313
65550221231205
7640153663256
oct140707106125
936507644055
1013004213333
1155735a2a51
12262b102505
1312c32186b7
148b5144b2d
155119d53a8
hex3071c8c55

13004213333 has 2 divisors, whose sum is σ = 13004213334. Its totient is φ = 13004213332.

The previous prime is 13004213329. The next prime is 13004213351. The reversal of 13004213333 is 33331240031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12973665604 + 30547729 = 113902^2 + 5527^2 .

It is a cyclic number.

It is not a de Polignac number, because 13004213333 - 22 = 13004213329 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13004213299 and 13004213308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13004213323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502106666 + 6502106667.

It is an arithmetic number, because the mean of its divisors is an integer number (6502106667).

Almost surely, 213004213333 is an apocalyptic number.

It is an amenable number.

13004213333 is a deficient number, since it is larger than the sum of its proper divisors (1).

13004213333 is an equidigital number, since it uses as much as digits as its factorization.

13004213333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 23.

Adding to 13004213333 its reverse (33331240031), we get a palindrome (46335453364).

The spelling of 13004213333 in words is "thirteen billion, four million, two hundred thirteen thousand, three hundred thirty-three".