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13004233169 is a prime number
BaseRepresentation
bin11000001110001110…
…01101100111010001
31020120021202111021112
430013013031213101
5203113040430134
65550221503105
7640154105144
oct140707154721
936507674245
1013004233169
115573606944
12262b111a95
1312c3224735
148b514c05b
155119db1ce
hex3071cd9d1

13004233169 has 2 divisors, whose sum is σ = 13004233170. Its totient is φ = 13004233168.

The previous prime is 13004233139. The next prime is 13004233237. The reversal of 13004233169 is 96133240031.

13004233169 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11856378769 + 1147854400 = 108887^2 + 33880^2 .

It is a cyclic number.

It is not a de Polignac number, because 13004233169 - 224 = 12987455953 is a prime.

It is a super-2 number, since 2×130042331692 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13004233139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502116584 + 6502116585.

It is an arithmetic number, because the mean of its divisors is an integer number (6502116585).

Almost surely, 213004233169 is an apocalyptic number.

It is an amenable number.

13004233169 is a deficient number, since it is larger than the sum of its proper divisors (1).

13004233169 is an equidigital number, since it uses as much as digits as its factorization.

13004233169 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11664, while the sum is 32.

The spelling of 13004233169 in words is "thirteen billion, four million, two hundred thirty-three thousand, one hundred sixty-nine".