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130042527084319 is a prime number
BaseRepresentation
bin11101100100010111100010…
…101000011110111100011111
3122001102221111022020000020211
4131210113202220132330133
5114021104043413144234
61140324413500553251
736251156023024153
oct3544274250367437
9561387438200224
10130042527084319
11384877a9379103
1212703143252827
135773c5b05a9c5
14241814022b063
151007a87d5b164
hex7645e2a1ef1f

130042527084319 has 2 divisors, whose sum is σ = 130042527084320. Its totient is φ = 130042527084318.

The previous prime is 130042527084271. The next prime is 130042527084397. The reversal of 130042527084319 is 913480725240031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 130042527084319 - 223 = 130042518695711 is a prime.

It is a super-2 number, since 2×1300425270843192 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130042521084319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65021263542159 + 65021263542160.

It is an arithmetic number, because the mean of its divisors is an integer number (65021263542160).

Almost surely, 2130042527084319 is an apocalyptic number.

130042527084319 is a deficient number, since it is larger than the sum of its proper divisors (1).

130042527084319 is an equidigital number, since it uses as much as digits as its factorization.

130042527084319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1451520, while the sum is 49.

The spelling of 130042527084319 in words is "one hundred thirty trillion, forty-two billion, five hundred twenty-seven million, eighty-four thousand, three hundred nineteen".