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1300430423400 = 233523779741493
BaseRepresentation
bin10010111011000111101…
…100011000010101101000
311121022122020021020010120
4102323013230120111220
5132301240142022100
62433224241043240
7162644610134163
oct22730754302550
94538566236116
101300430423400
11461567087709
12190047626520
139582632b644
1446d267ccada
1523c61ae80a0
hex12ec7b18568

1300430423400 has 192 divisors, whose sum is σ = 4192703673600. Its totient is φ = 333137525760.

The previous prime is 1300430423389. The next prime is 1300430423401. The reversal of 1300430423400 is 43240340031.

It is a super-2 number, since 2×13004304234002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is not an unprimeable number, because it can be changed into a prime (1300430423401) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1383054 + ... + 2124546.

It is an arithmetic number, because the mean of its divisors is an integer number (21836998300).

Almost surely, 21300430423400 is an apocalyptic number.

1300430423400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1300430423400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2096351836800).

1300430423400 is an abundant number, since it is smaller than the sum of its proper divisors (2892273250200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300430423400 is a wasteful number, since it uses less digits than its factorization.

1300430423400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 741628 (or 741619 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 24.

Adding to 1300430423400 its reverse (43240340031), we get a palindrome (1343670763431).

The spelling of 1300430423400 in words is "one trillion, three hundred billion, four hundred thirty million, four hundred twenty-three thousand, four hundred".