130043321235 has 64 divisors (see below), whose sum is σ = 242503925760. Its totient is φ = 65993304960.

The previous prime is 130043321203. The next prime is 130043321269. The reversal of 130043321235 is 532123340031.

130043321235 is a `hidden beast` number, since 1 + 300 + 4 + 3 + 321 + 2 + 35 = 666.

It is not a de Polignac number, because 130043321235 - 2⁵ = 130043321203 is a prime.

It is a super-2 number, since 2×130043321235² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 130043321199 and 130043321208.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 483417 + ... + 702693.

It is an arithmetic number, because the mean of its divisors is an integer number (3789123840).

Almost surely, 2^130043321235 is an apocalyptic number.

130043321235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

130043321235 is a deficient number, since it is larger than the sum of its proper divisors (112460604525).

130043321235 is a wasteful number, since it uses less digits than its factorization.

130043321235 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 219505 (or 219499 counting only the distinct ones).

The product of its (nonzero) digits is 6480, while the sum is 27.

Adding to 130043321235 its reverse (532123340031), we get a palindrome (662166661266).

The spelling of 130043321235 in words is "one hundred thirty billion, forty-three million, three hundred twenty-one thousand, two hundred thirty-five".