13004333340031 has 16 divisors (see below), whose sum is σ = 14320531209600. Its totient is φ = 11710524520800.

The previous prime is 13004333340029. The next prime is 13004333340127.

13004333340031 is nontrivially palindromic in base 10.

It is a cyclic number.

It is not a de Polignac number, because 13004333340031 - 2¹ = 13004333340029 is a prime.

It is a super-2 number, since 2×13004333340031² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13004333320031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3032676 + ... + 5933446.

It is an arithmetic number, because the mean of its divisors is an integer number (895033200600).

Almost surely, 2^{13004333340031} is an apocalyptic number.

13004333340031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13004333340031 is a deficient number, since it is larger than the sum of its proper divisors (1316197869569).

13004333340031 is a wasteful number, since it uses less digits than its factorization.

13004333340031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2904630.

The product of its (nonzero) digits is 11664, while the sum is 28.

It can be divided in two parts, 1300433 and 3340031, that added together give a palindrome (4640464).

The spelling of 13004333340031 in words is "thirteen trillion, four billion, three hundred thirty-three million, three hundred forty thousand, thirty-one".