Base | Representation |
---|---|
bin | 1011110100111100111010… |
… | …1010110101010101111110 |
3 | 1201001012110100110000021200 |
4 | 2331033032222311111332 |
5 | 3201030333313340110 |
6 | 43354035215040330 |
7 | 2511350334363654 |
oct | 275171652652576 |
9 | 51035410400250 |
10 | 13004333340030 |
11 | 416411a16a24a |
12 | 15603b0b100a6 |
13 | 7343c367bc46 |
14 | 32d5ad74add4 |
15 | 178414d046c0 |
hex | bd3ceab557e |
13004333340030 has 48 divisors (see below), whose sum is σ = 33821936806320. Its totient is φ = 3466727852544.
The previous prime is 13004333340029. The next prime is 13004333340127. The reversal of 13004333340030 is 3004333340031.
13004333340030 is a `hidden beast` number, since 130 + 0 + 433 + 33 + 40 + 0 + 30 = 666.
It is a super-2 number, since 2×130043333400302 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13004333339976 and 13004333340003.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 22512612 + ... + 23083031.
It is an arithmetic number, because the mean of its divisors is an integer number (704623683465).
Almost surely, 213004333340030 is an apocalyptic number.
13004333340030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13004333340030 is an abundant number, since it is smaller than the sum of its proper divisors (20817603466290).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13004333340030 is a wasteful number, since it uses less digits than its factorization.
13004333340030 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45598825 (or 45598822 counting only the distinct ones).
The product of its (nonzero) digits is 11664, while the sum is 27.
Adding to 13004333340030 its reverse (3004333340031), we get a palindrome (16008666680061).
Subtracting from 13004333340030 its reverse (3004333340031), we obtain a palindrome (9999999999999).
The spelling of 13004333340030 in words is "thirteen trillion, four billion, three hundred thirty-three million, three hundred forty thousand, thirty".
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