13004333340127 has 2 divisors, whose sum is σ = 13004333340128. Its totient is φ = 13004333340126.

The previous prime is 13004333340029. The next prime is 13004333340133. The reversal of 13004333340127 is 72104333340031.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13004333340127 is a prime.

It is a super-4 number, since 4×13004333340127⁴ (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 13004333340092 and 13004333340101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13004333340157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502166670063 + 6502166670064.

It is an arithmetic number, because the mean of its divisors is an integer number (6502166670064).

Almost surely, 2^{13004333340127} is an apocalyptic number.

13004333340127 is a deficient number, since it is larger than the sum of its proper divisors (1).

13004333340127 is an equidigital number, since it uses as much as digits as its factorization.

13004333340127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54432, while the sum is 34.

Adding to 13004333340127 its reverse (72104333340031), we get a palindrome (85108666680158).

The spelling of 13004333340127 in words is "thirteen trillion, four billion, three hundred thirty-three million, three hundred forty thousand, one hundred twenty-seven".