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13004341411 is a prime number
BaseRepresentation
bin11000001110001111…
…01000000010100011
31020120021221222202111
430013013220002203
5203113102411121
65550224100151
7640155035545
oct140707500243
936507858674
1013004341411
1155736801a6
12262b164657
1312c3261a99
148b5179695
15511a0d2e1
hex3071e80a3

13004341411 has 2 divisors, whose sum is σ = 13004341412. Its totient is φ = 13004341410.

The previous prime is 13004341397. The next prime is 13004341421. The reversal of 13004341411 is 11414340031.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13004341411 - 223 = 12995952803 is a prime.

It is a super-2 number, since 2×130043414112 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13004341421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502170705 + 6502170706.

It is an arithmetic number, because the mean of its divisors is an integer number (6502170706).

Almost surely, 213004341411 is an apocalyptic number.

13004341411 is a deficient number, since it is larger than the sum of its proper divisors (1).

13004341411 is an equidigital number, since it uses as much as digits as its factorization.

13004341411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 13004341411 its reverse (11414340031), we get a palindrome (24418681442).

The spelling of 13004341411 in words is "thirteen billion, four million, three hundred forty-one thousand, four hundred eleven".