Base | Representation |
---|---|
bin | 11000001110001111… |
… | …01000000010100011 |
3 | 1020120021221222202111 |
4 | 30013013220002203 |
5 | 203113102411121 |
6 | 5550224100151 |
7 | 640155035545 |
oct | 140707500243 |
9 | 36507858674 |
10 | 13004341411 |
11 | 55736801a6 |
12 | 262b164657 |
13 | 12c3261a99 |
14 | 8b5179695 |
15 | 511a0d2e1 |
hex | 3071e80a3 |
13004341411 has 2 divisors, whose sum is σ = 13004341412. Its totient is φ = 13004341410.
The previous prime is 13004341397. The next prime is 13004341421. The reversal of 13004341411 is 11414340031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13004341411 - 223 = 12995952803 is a prime.
It is a super-2 number, since 2×130043414112 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13004341421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502170705 + 6502170706.
It is an arithmetic number, because the mean of its divisors is an integer number (6502170706).
Almost surely, 213004341411 is an apocalyptic number.
13004341411 is a deficient number, since it is larger than the sum of its proper divisors (1).
13004341411 is an equidigital number, since it uses as much as digits as its factorization.
13004341411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 13004341411 its reverse (11414340031), we get a palindrome (24418681442).
The spelling of 13004341411 in words is "thirteen billion, four million, three hundred forty-one thousand, four hundred eleven".
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