Base | Representation |
---|---|
bin | 11000001110001111… |
… | …01000000010111001 |
3 | 1020120021221222210022 |
4 | 30013013220002321 |
5 | 203113102411213 |
6 | 5550224100225 |
7 | 640155035606 |
oct | 140707500271 |
9 | 36507858708 |
10 | 13004341433 |
11 | 5573680216 |
12 | 262b164675 |
13 | 12c3261ab5 |
14 | 8b51796ad |
15 | 511a0d308 |
hex | 3071e80b9 |
13004341433 has 2 divisors, whose sum is σ = 13004341434. Its totient is φ = 13004341432.
The previous prime is 13004341421. The next prime is 13004341457. The reversal of 13004341433 is 33414340031.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12633085609 + 371255824 = 112397^2 + 19268^2 .
It is a cyclic number.
It is not a de Polignac number, because 13004341433 - 224 = 12987564217 is a prime.
It is a super-2 number, since 2×130043414332 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13004341463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502170716 + 6502170717.
It is an arithmetic number, because the mean of its divisors is an integer number (6502170717).
Almost surely, 213004341433 is an apocalyptic number.
It is an amenable number.
13004341433 is a deficient number, since it is larger than the sum of its proper divisors (1).
13004341433 is an equidigital number, since it uses as much as digits as its factorization.
13004341433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 13004341433 its reverse (33414340031), we get a palindrome (46418681464).
The spelling of 13004341433 in words is "thirteen billion, four million, three hundred forty-one thousand, four hundred thirty-three".
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