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13004342213 is a prime number
BaseRepresentation
bin11000001110001111…
…01000001111000101
31020120021222000212012
430013013220033011
5203113102422323
65550224104005
7640155041102
oct140707501705
936507860765
1013004342213
115573680865
12262b165005
1312c3262265
148b5179aa9
15511a0d678
hex3071e83c5

13004342213 has 2 divisors, whose sum is σ = 13004342214. Its totient is φ = 13004342212.

The previous prime is 13004342207. The next prime is 13004342227. The reversal of 13004342213 is 31224340031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11121389764 + 1882952449 = 105458^2 + 43393^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13004342213 is a prime.

It is a super-2 number, since 2×130043422132 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13004342513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502171106 + 6502171107.

It is an arithmetic number, because the mean of its divisors is an integer number (6502171107).

Almost surely, 213004342213 is an apocalyptic number.

It is an amenable number.

13004342213 is a deficient number, since it is larger than the sum of its proper divisors (1).

13004342213 is an equidigital number, since it uses as much as digits as its factorization.

13004342213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 13004342213 its reverse (31224340031), we get a palindrome (44228682244).

The spelling of 13004342213 in words is "thirteen billion, four million, three hundred forty-two thousand, two hundred thirteen".