Base | Representation |
---|---|
bin | 111100100011100111… |
… | …0011111011100000010 |
3 | 110102122222201200021112 |
4 | 1321013032133130002 |
5 | 4112312231000002 |
6 | 135424050123322 |
7 | 12252416522150 |
oct | 1710716373402 |
9 | 412588650245 |
10 | 130044000002 |
11 | 501734a1a74 |
12 | 21253580542 |
13 | c35603bc37 |
14 | 64192803d0 |
15 | 35b1b55852 |
hex | 1e4739f702 |
130044000002 has 32 divisors (see below), whose sum is σ = 232274718720. Its totient is φ = 53431212240.
The previous prime is 130043999989. The next prime is 130044000017. The reversal of 130044000002 is 200000440031.
It is a super-2 number, since 2×1300440000022 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (14).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1353752 + ... + 1446627.
It is an arithmetic number, because the mean of its divisors is an integer number (7258584960).
Almost surely, 2130044000002 is an apocalyptic number.
130044000002 is a deficient number, since it is larger than the sum of its proper divisors (102230718718).
130044000002 is a wasteful number, since it uses less digits than its factorization.
130044000002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2800526.
The product of its (nonzero) digits is 96, while the sum is 14.
Adding to 130044000002 its reverse (200000440031), we get a palindrome (330044440033).
The spelling of 130044000002 in words is "one hundred thirty billion, forty-four million, two", and thus it is an aban number.
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