Base | Representation |
---|---|
bin | 10010111011001000010… |
… | …001000010100000111110 |
3 | 11121022122220100110111100 |
4 | 102323020101002200332 |
5 | 132301300122031332 |
6 | 2433225223033530 |
7 | 162645054620412 |
oct | 22731021024076 |
9 | 4538586313440 |
10 | 1300440033342 |
11 | 46157155080a |
12 | 19004a89b8a6 |
13 | 958283147b8 |
14 | 46d27bb0d42 |
15 | 23c6289567c |
hex | 12ec844283e |
1300440033342 has 24 divisors (see below), whose sum is σ = 2832372017280. Its totient is φ = 431210481120.
The previous prime is 1300440033307. The next prime is 1300440033383. The reversal of 1300440033342 is 2433300440031.
It is a super-2 number, since 2×13004400333422 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 189123967 + ... + 189130842.
It is an arithmetic number, because the mean of its divisors is an integer number (118015500720).
Almost surely, 21300440033342 is an apocalyptic number.
1300440033342 is an abundant number, since it is smaller than the sum of its proper divisors (1531931983938).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1300440033342 is a wasteful number, since it uses less digits than its factorization.
1300440033342 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 378255008 (or 378255005 counting only the distinct ones).
The product of its (nonzero) digits is 10368, while the sum is 27.
Adding to 1300440033342 its reverse (2433300440031), we get a palindrome (3733740473373).
The spelling of 1300440033342 in words is "one trillion, three hundred billion, four hundred forty million, thirty-three thousand, three hundred forty-two".
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