Base | Representation |
---|---|
bin | 11000001110001111… |
… | …10110011100011100 |
3 | 1020120022001222200201 |
4 | 30013013312130130 |
5 | 203113111303122 |
6 | 5550225233244 |
7 | 640155402553 |
oct | 140707663434 |
9 | 36508058621 |
10 | 13004400412 |
11 | 5573710563 |
12 | 262b192824 |
13 | 12c32828b3 |
14 | 8b5192d9a |
15 | 511a20a27 |
hex | 3071f671c |
13004400412 has 12 divisors (see below), whose sum is σ = 23130778216. Its totient is φ = 6395606640.
The previous prime is 13004400403. The next prime is 13004400419. The reversal of 13004400412 is 21400440031.
It is a super-2 number, since 2×130044004122 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13004400412.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13004400419) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26648118 + ... + 26648605.
Almost surely, 213004400412 is an apocalyptic number.
It is an amenable number.
13004400412 is a deficient number, since it is larger than the sum of its proper divisors (10126377804).
13004400412 is a wasteful number, since it uses less digits than its factorization.
13004400412 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53296788 (or 53296786 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 19.
Adding to 13004400412 its reverse (21400440031), we get a palindrome (34404840443).
The spelling of 13004400412 in words is "thirteen billion, four million, four hundred thousand, four hundred twelve".
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