Base | Representation |
---|---|
bin | 11000001110001111… |
… | …10110111000010101 |
3 | 1020120022002002010211 |
4 | 30013013312320111 |
5 | 203113111332242 |
6 | 5550225245421 |
7 | 640155411013 |
oct | 140707667025 |
9 | 36508062124 |
10 | 13004402197 |
11 | 5573711936 |
12 | 262b193871 |
13 | 12c3283657 |
14 | 8b51938b3 |
15 | 511a21317 |
hex | 3071f6e15 |
13004402197 has 2 divisors, whose sum is σ = 13004402198. Its totient is φ = 13004402196.
The previous prime is 13004402189. The next prime is 13004402221. The reversal of 13004402197 is 79120440031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8202743761 + 4801658436 = 90569^2 + 69294^2 .
It is an emirp because it is prime and its reverse (79120440031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13004402197 - 23 = 13004402189 is a prime.
It is a super-2 number, since 2×130044021972 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13004402107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502201098 + 6502201099.
It is an arithmetic number, because the mean of its divisors is an integer number (6502201099).
Almost surely, 213004402197 is an apocalyptic number.
It is an amenable number.
13004402197 is a deficient number, since it is larger than the sum of its proper divisors (1).
13004402197 is an equidigital number, since it uses as much as digits as its factorization.
13004402197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 31.
The spelling of 13004402197 in words is "thirteen billion, four million, four hundred two thousand, one hundred ninety-seven".
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