Base | Representation |
---|---|
bin | 11000001110001111… |
… | …10111011011000100 |
3 | 1020120022002012012011 |
4 | 30013013313123010 |
5 | 203113111420140 |
6 | 5550225304004 |
7 | 640155420340 |
oct | 140707673304 |
9 | 36508065164 |
10 | 13004404420 |
11 | 5573713577 |
12 | 262b195004 |
13 | 12c3284677 |
14 | 8b5194620 |
15 | 511a21cea |
hex | 3071f76c4 |
13004404420 has 96 divisors (see below), whose sum is σ = 31518369792. Its totient is φ = 4414860288.
The previous prime is 13004404331. The next prime is 13004404421. The reversal of 13004404420 is 2440440031.
It is a super-2 number, since 2×130044044202 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13004404391 and 13004404400.
It is not an unprimeable number, because it can be changed into a prime (13004404421) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11641702 + ... + 11642818.
It is an arithmetic number, because the mean of its divisors is an integer number (328316352).
Almost surely, 213004404420 is an apocalyptic number.
13004404420 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13004404420, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15759184896).
13004404420 is an abundant number, since it is smaller than the sum of its proper divisors (18513965372).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13004404420 is a wasteful number, since it uses less digits than its factorization.
13004404420 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1877 (or 1875 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 22.
Adding to 13004404420 its reverse (2440440031), we get a palindrome (15444844451).
The spelling of 13004404420 in words is "thirteen billion, four million, four hundred four thousand, four hundred twenty".
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