Base | Representation |
---|---|
bin | 11000001110010000… |
… | …00011010011101101 |
3 | 1020120022011122222011 |
4 | 30013020003103231 |
5 | 203113114444401 |
6 | 5550230321221 |
7 | 640156012303 |
oct | 140710032355 |
9 | 36508148864 |
10 | 13004453101 |
11 | 5573747102 |
12 | 262b1b9211 |
13 | 12c32a0883 |
14 | 8b51a8273 |
15 | 511a31451 |
hex | 3072034ed |
13004453101 has 2 divisors, whose sum is σ = 13004453102. Its totient is φ = 13004453100.
The previous prime is 13004453071. The next prime is 13004453117. The reversal of 13004453101 is 10135440031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8901922500 + 4102530601 = 94350^2 + 64051^2 .
It is a cyclic number.
It is not a de Polignac number, because 13004453101 - 229 = 12467582189 is a prime.
It is a super-2 number, since 2×130044531012 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13004453191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502226550 + 6502226551.
It is an arithmetic number, because the mean of its divisors is an integer number (6502226551).
Almost surely, 213004453101 is an apocalyptic number.
It is an amenable number.
13004453101 is a deficient number, since it is larger than the sum of its proper divisors (1).
13004453101 is an equidigital number, since it uses as much as digits as its factorization.
13004453101 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 720, while the sum is 22.
Adding to 13004453101 its reverse (10135440031), we get a palindrome (23139893132).
The spelling of 13004453101 in words is "thirteen billion, four million, four hundred fifty-three thousand, one hundred one".
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