1300451232040 has 16 divisors (see below), whose sum is σ = 2926015272180. Its totient is φ = 520180492800.

The previous prime is 1300451232037. The next prime is 1300451232043. The reversal of 1300451232040 is 402321540031.

It is an interprime number because it is at equal distance from previous prime (1300451232037) and next prime (1300451232043).

It can be written as a sum of positive squares in 2 ways, for example, as 1214188017604 + 86263214436 = 1101902^2 + 293706^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1300451231996 and 1300451232014.

It is not an unprimeable number, because it can be changed into a prime (1300451232043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16255640361 + ... + 16255640440.

Almost surely, 2^{1300451232040} is an apocalyptic number.

1300451232040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1300451232040 is an abundant number, since it is smaller than the sum of its proper divisors (1625564040140).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300451232040 is a wasteful number, since it uses less digits than its factorization.

1300451232040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32511280812 (or 32511280808 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 1300451232040 its reverse (402321540031), we get a palindrome (1702772772071).

The spelling of 1300451232040 in words is "one trillion, three hundred billion, four hundred fifty-one million, two hundred thirty-two thousand, forty".