Base | Representation |
---|---|
bin | 10010111011001001001… |
… | …000111101110101001101 |
3 | 11121022200220221022102212 |
4 | 102323021020331311031 |
5 | 132301312400203341 |
6 | 2433230505200205 |
7 | 162645323341454 |
oct | 22731110756515 |
9 | 4538626838385 |
10 | 1300454694221 |
11 | 461579854741 |
12 | 190053790065 |
13 | 9582b378987 |
14 | 46d29b09b9b |
15 | 23c63cde5eb |
hex | 12ec923dd4d |
1300454694221 has 2 divisors, whose sum is σ = 1300454694222. Its totient is φ = 1300454694220.
The previous prime is 1300454694197. The next prime is 1300454694241. The reversal of 1300454694221 is 1224964540031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1280258305225 + 20196388996 = 1131485^2 + 142114^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1300454694221 is a prime.
It is a super-2 number, since 2×13004546942212 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1300454694241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650227347110 + 650227347111.
It is an arithmetic number, because the mean of its divisors is an integer number (650227347111).
Almost surely, 21300454694221 is an apocalyptic number.
It is an amenable number.
1300454694221 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300454694221 is an equidigital number, since it uses as much as digits as its factorization.
1300454694221 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 207360, while the sum is 41.
The spelling of 1300454694221 in words is "one trillion, three hundred billion, four hundred fifty-four million, six hundred ninety-four thousand, two hundred twenty-one".
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