Search a number
-
+
13004719102 = 26502359551
BaseRepresentation
bin11000001110010010…
…00100001111111110
31020120022200011212001
430013021010033332
5203113202002402
65550240132514
7640161200644
oct140711041776
936508604761
1013004719102
115573908a41
12262b30713a
1312c336497b
148b5237194
15511a85187
hex3072443fe

13004719102 has 4 divisors (see below), whose sum is σ = 19507078656. Its totient is φ = 6502359550.

The previous prime is 13004719099. The next prime is 13004719103. The reversal of 13004719102 is 20191740031.

13004719102 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 20191740031 = 53380976227.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13004719103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3251179774 + ... + 3251179777.

It is an arithmetic number, because the mean of its divisors is an integer number (4876769664).

Almost surely, 213004719102 is an apocalyptic number.

13004719102 is a deficient number, since it is larger than the sum of its proper divisors (6502359554).

13004719102 is an equidigital number, since it uses as much as digits as its factorization.

13004719102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6502359553.

The product of its (nonzero) digits is 1512, while the sum is 28.

The spelling of 13004719102 in words is "thirteen billion, four million, seven hundred nineteen thousand, one hundred two".

Divisors: 1 2 6502359551 13004719102