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13004749003 is a prime number
BaseRepresentation
bin11000001110010010…
…01011100011001011
31020120022201200212111
430013021023203023
5203113203432003
65550240523151
7640161354061
oct140711134313
936508650774
1013004749003
115573929454
12262b3204b7
1312c337546c
148b5244031
15511a8de6d
hex30724b8cb

13004749003 has 2 divisors, whose sum is σ = 13004749004. Its totient is φ = 13004749002.

The previous prime is 13004749001. The next prime is 13004749039. The reversal of 13004749003 is 30094740031.

It is a weak prime.

It is an emirp because it is prime and its reverse (30094740031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13004749003 - 21 = 13004749001 is a prime.

Together with 13004749001, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13004749001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502374501 + 6502374502.

It is an arithmetic number, because the mean of its divisors is an integer number (6502374502).

Almost surely, 213004749003 is an apocalyptic number.

13004749003 is a deficient number, since it is larger than the sum of its proper divisors (1).

13004749003 is an equidigital number, since it uses as much as digits as its factorization.

13004749003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9072, while the sum is 31.

The spelling of 13004749003 in words is "thirteen billion, four million, seven hundred forty-nine thousand, three".