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130049251 is a prime number
BaseRepresentation
bin1111100000001…
…10010011100011
3100001201012000221
413300012103203
5231243034001
620523223511
73136254223
oct760062343
9301635027
10130049251
1167455a22
1237677b97
1320c35027
14133b4083
15b63d1a1
hex7c064e3

130049251 has 2 divisors, whose sum is σ = 130049252. Its totient is φ = 130049250.

The previous prime is 130049219. The next prime is 130049267. The reversal of 130049251 is 152940031.

It is a strong prime.

It is an emirp because it is prime and its reverse (152940031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130049251 - 25 = 130049219 is a prime.

It is a super-2 number, since 2×1300492512 = 33825615371322002, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130049951) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65024625 + 65024626.

It is an arithmetic number, because the mean of its divisors is an integer number (65024626).

Almost surely, 2130049251 is an apocalyptic number.

130049251 is a deficient number, since it is larger than the sum of its proper divisors (1).

130049251 is an equidigital number, since it uses as much as digits as its factorization.

130049251 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1080, while the sum is 25.

The square root of 130049251 is about 11403.9138456935. The cubic root of 130049251 is about 506.6436670558.

Adding to 130049251 its reverse (152940031), we get a palindrome (282989282).

The spelling of 130049251 in words is "one hundred thirty million, forty-nine thousand, two hundred fifty-one".