Base | Representation |
---|---|
bin | 10010111011001100100… |
… | …100000100111111101111 |
3 | 11121022211221000111202212 |
4 | 102323030210010333233 |
5 | 132301422101224403 |
6 | 2433240320241035 |
7 | 162646621510661 |
oct | 22731444047757 |
9 | 4538757014685 |
10 | 1300512133103 |
11 | 4615a9216397 |
12 | 19006aa7017b |
13 | 9583a239c91 |
14 | 46d335bc531 |
15 | 23c68d884d8 |
hex | 12ecc904fef |
1300512133103 has 2 divisors, whose sum is σ = 1300512133104. Its totient is φ = 1300512133102.
The previous prime is 1300512133079. The next prime is 1300512133139. The reversal of 1300512133103 is 3013312150031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1300512133103 - 28 = 1300512132847 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1300512133003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650256066551 + 650256066552.
It is an arithmetic number, because the mean of its divisors is an integer number (650256066552).
Almost surely, 21300512133103 is an apocalyptic number.
1300512133103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300512133103 is an equidigital number, since it uses as much as digits as its factorization.
1300512133103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 810, while the sum is 23.
Adding to 1300512133103 its reverse (3013312150031), we get a palindrome (4313824283134).
The spelling of 1300512133103 in words is "one trillion, three hundred billion, five hundred twelve million, one hundred thirty-three thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.402 sec. • engine limits •