Base | Representation |
---|---|
bin | 111100100011110101… |
… | …0110100010001000011 |
3 | 110102200111200220221022 |
4 | 1321013222310101003 |
5 | 4112321131102342 |
6 | 135424513220055 |
7 | 12252536606324 |
oct | 1710752642103 |
9 | 412614626838 |
10 | 130051425347 |
11 | 50177703818 |
12 | 21255b6162b |
13 | c35773b92c |
14 | 641a25444b |
15 | 35b26209d2 |
hex | 1e47ab4443 |
130051425347 has 2 divisors, whose sum is σ = 130051425348. Its totient is φ = 130051425346.
The previous prime is 130051425233. The next prime is 130051425353. The reversal of 130051425347 is 743524150031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130051425347 is a prime.
It is not a weakly prime, because it can be changed into another prime (130051425947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65025712673 + 65025712674.
It is an arithmetic number, because the mean of its divisors is an integer number (65025712674).
Almost surely, 2130051425347 is an apocalyptic number.
130051425347 is a deficient number, since it is larger than the sum of its proper divisors (1).
130051425347 is an equidigital number, since it uses as much as digits as its factorization.
130051425347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50400, while the sum is 35.
Adding to 130051425347 its reverse (743524150031), we get a palindrome (873575575378).
The spelling of 130051425347 in words is "one hundred thirty billion, fifty-one million, four hundred twenty-five thousand, three hundred forty-seven".
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