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130051425353 is a prime number
BaseRepresentation
bin111100100011110101…
…0110100010001001001
3110102200111200220221112
41321013222310101021
54112321131102403
6135424513220105
712252536606333
oct1710752642111
9412614626845
10130051425353
1150177703823
1221255b61635
13c35773b935
14641a254453
1535b26209d8
hex1e47ab4449

130051425353 has 2 divisors, whose sum is σ = 130051425354. Its totient is φ = 130051425352.

The previous prime is 130051425347. The next prime is 130051425389. The reversal of 130051425353 is 353524150031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 102955631689 + 27095793664 = 320867^2 + 164608^2 .

It is a cyclic number.

It is not a de Polignac number, because 130051425353 - 210 = 130051424329 is a prime.

It is not a weakly prime, because it can be changed into another prime (130051325353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65025712676 + 65025712677.

It is an arithmetic number, because the mean of its divisors is an integer number (65025712677).

Almost surely, 2130051425353 is an apocalyptic number.

It is an amenable number.

130051425353 is a deficient number, since it is larger than the sum of its proper divisors (1).

130051425353 is an equidigital number, since it uses as much as digits as its factorization.

130051425353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27000, while the sum is 32.

Adding to 130051425353 its reverse (353524150031), we get a palindrome (483575575384).

The spelling of 130051425353 in words is "one hundred thirty billion, fifty-one million, four hundred twenty-five thousand, three hundred fifty-three".