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130051433 is a prime number
BaseRepresentation
bin1111100000001…
…10110101101001
3100001201022000202
413300012311221
5231243121213
620523241545
73136263461
oct760066551
9301638022
10130051433
1167457626
12376792b5
1320c36015
14133b4ba1
15b63db58
hex7c06d69

130051433 has 2 divisors, whose sum is σ = 130051434. Its totient is φ = 130051432.

The previous prime is 130051387. The next prime is 130051463. The reversal of 130051433 is 334150031.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 68773849 + 61277584 = 8293^2 + 7828^2 .

It is a cyclic number.

It is not a de Polignac number, because 130051433 - 210 = 130050409 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (130051463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65025716 + 65025717.

It is an arithmetic number, because the mean of its divisors is an integer number (65025717).

Almost surely, 2130051433 is an apocalyptic number.

It is an amenable number.

130051433 is a deficient number, since it is larger than the sum of its proper divisors (1).

130051433 is an equidigital number, since it uses as much as digits as its factorization.

130051433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 20.

The square root of 130051433 is about 11404.0095142016. The cubic root of 130051433 is about 506.6465005728.

The spelling of 130051433 in words is "one hundred thirty million, fifty-one thousand, four hundred thirty-three".