Base | Representation |
---|---|
bin | 1011110101000000001011… |
… | …1111101001100011100100 |
3 | 1201001021201112022112020111 |
4 | 2331100002333221203210 |
5 | 3201034133032241004 |
6 | 43354302254542404 |
7 | 2511411154231324 |
oct | 275200277514344 |
9 | 51037645275214 |
10 | 13005211212004 |
11 | 416452a758480 |
12 | 15605b6b07a04 |
13 | 7345034c870b |
14 | 32d654187284 |
15 | 178466e0ea04 |
hex | bd402fe98e4 |
13005211212004 has 96 divisors (see below), whose sum is σ = 25650652962816. Its totient is φ = 5718820154880.
The previous prime is 13005211212001. The next prime is 13005211212017. The reversal of 13005211212004 is 40021211250031.
13005211212004 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (22).
It is not an unprimeable number, because it can be changed into a prime (13005211212001) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 85686207 + ... + 85837849.
It is an arithmetic number, because the mean of its divisors is an integer number (267194301696).
Almost surely, 213005211212004 is an apocalyptic number.
It is an amenable number.
13005211212004 is a deficient number, since it is larger than the sum of its proper divisors (12645441750812).
13005211212004 is a wasteful number, since it uses less digits than its factorization.
13005211212004 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 152185 (or 152183 counting only the distinct ones).
The product of its (nonzero) digits is 480, while the sum is 22.
Adding to 13005211212004 its reverse (40021211250031), we get a palindrome (53026422462035).
The spelling of 13005211212004 in words is "thirteen trillion, five billion, two hundred eleven million, two hundred twelve thousand, four".
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